24b^2-3b=0

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Solution for 24b^2-3b=0 equation: 



24b^2-3b=0

a = 24; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·24·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*24}=\frac{0}{48}
=0
$


$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*24}=\frac{6}{48}
=1/8
$

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